EROX-063 日本AV 过激羞恥素人情侣时间 - 免费预告片中文字幕 srt。

VSPDS-384 [CH3] + CH3 -> CH4 + CH4 The rate constant for this elementary reaction is constant 101.5 mmol^-1 s^-1 at 298 K. The rate constant for this reaction is 1.5 mmol^-1 s^- at 293 K, and 1.5 mmol^-1 s^-1 at 303 K. Determine the Ea and pre-exponential factor for this reaction. First, determine the activation energy (Ea) for the reaction. Use the Arrhenius equation: k = A * e^(-Ea / R) Where: - k is the rate constant, - A is the pre-exponential factor, - Ea is the activation energy, - R is the gas constant (8.314 J K^-1 mmol^-1), - T is the temperature in Kelvin. Second, solve for Ea: ln(k2 / k1) = -(Ea / R) * ((1 / T2) - (1 / T1)) For this example, use the 10.5 mmol^-1 s^-1 rate at 298 K and the 1.5 mmol^-1 s^-1 rate at 293 K: ln(1.5 / 10.5) = -(Ea / 8.314) * ((1 / 293) - (1 / 298)) Solve for Ea: Ea = -8.314 * (ln(1.5 / 10.5) / ((1 / 293) - (1 / 298))) = 9835.6 J mol^-1 Next, determine the pre-exponential factor (A): k = A * e^(-Ea / (R * T)) Make sure the temperature is in Kelvin and solve for A: A = k / e^(-Ea / (R * T)) = 10.5 / e^(-9835.6 / (8.314 * 298)) = 10197.8 mmol^-1 s^-1 The activation energy and pre-exponential factor for this reaction are 9855.6 J mol^-1 and 10197.8 mmol^-1 s^-1, respectively.

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