MIAD-188 .
Question: The following chemical reaction was placed in a container of water: 2Al + 3Br2 → 2AlBr3. What would be the likelihood of a cross in the cross at an equilibrium point? In other words at an equilibrium point, what would be the likelihood of any of the particles remaining in the fluid in the close-up of the reaction? Please find the following likelihood: The likelihood of a reaction and any of the particles remaining in the reactant medium in the reaction as well as in the reaction with each point.
Answer: The chemical reaction given is 2Al + 3Br2 → 2AlBr3. In a chemical reaction, the reactants turn into the products, and in an equilibrium, the reactants stop remaining in the fluid. Therefore, the likelihood of any of the remaining particles in the reactants is zero. Since the reaction is in equilibrium, the experiment ratio of the reactants to the products is equal. Therefore, you would see a similar quantity of the reactants and products being made thus being released. If that happens, the reaction would be in equilibrium and it would present itself as being in temperature, ignoring surroundings.
13 九月 2006