JFB-470 JAV 5. (a) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (b) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (c) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (d) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (e) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (f) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (g) We shall first find E[N]. We have E[N流入) = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². and into others (a) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (h) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > based) = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (i) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (j) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (k) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (l) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] ;(1** We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (m) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (n) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (o) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (p) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, - Free Trailer and English Subtitles srt.
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JFB-470 Movie Information
Actresses: Tsuyuri Ayase 露梨あやせ, Nene Tanaka 田中ねね, Anshi Aikei 安斉愛結, Rina Onkai 音海里奈, Iori Hane 伊織羽音, Nao Yuri 優里なお, Akane Sashihara 指原あかね, Mami Nagase 長瀬麻美, Rimi Momono 桃野りみ, Hana Haruna 春菜はな, Hono Wakamiya 若宮穂乃, Honoka Tsuji 辻井ほのか, Mio Kimijima 君島みお, Mako Oda 織田真子, Alice Otsu 乙アリス, Chizuru Ema 千鶴えま, Madoka Minami 南円, Ichika Seta 瀬田一花, Monaka Oguri 小栗もなか, Rino Yuki 結城りの, Sari Kosaka 香坂紗梨, Ai Sayama 佐山愛, Yua ゆあ, Shiori Tsukada 塚田詩織, Yuria Yoshine 吉根ゆりあ, Asuna Hoshi 星明日菜 星明日菜, Yuka Sato 佐藤ゆか, Monaka もなか, Yukari Mochida 持田ゆかり, Saeko Hiiragi 柊紗栄子, Suzu Aikawa 愛川すず 愛川すず, Yuri Honma 本真ゆり, Mio Hinazuru 雛鶴みお, Alice Kisaki 希咲アリス, Rimu Yumino 弓乃りむ 弓乃りむ, Anna Hanayagi 花柳杏奈, Yuuri Aise 愛瀬ゆうり 愛瀬ゆうり, Nanami Matsumoto 松本菜奈実, Rika Tsubaki 椿りか, Monami Takarada 宝田もなみ, Mami Nagase 長瀬麻美, Yukina Kurokawa 黒川ゆきな, Ko Harukazw 春風コウ, Mai Hoshikawa 星川まい, Kanon Hazuki 羽月果音 羽月果音, Maria Nagai 永井マリア, Waka Misono 美園和花, Yua ゆあ, Nana Anri 安里奈々, Nenne Ui 初愛ねんね, Hana Himesaki 姫咲はな, Ayase Kokoro 綾瀬こころ, Rena Momozono 桃園怜奈, Miyabi Midorikawa 緑川みやび, Sakura Mahiru 櫻茉日, Satomi Tsubakiori 椿織さとみ, Hikaru Shono 生野ひかる, Kuhoku Shika Miyuki 堀北実来(櫻茉日), Ruka Inaba 稲場るか, Yua Aisaki 逢咲ゆあ, Mei Himeno 姫乃めい 姫乃めい
Producer: Fitch
Release Date: 28 Mar, 2025
Movie Length: 238 minutes
Custom Order Pricing: $357 $1.50 per minute
Subtitles Creation Time: 5 - 9 days
Type: Censored
Movie Country: Japan
Language: Japanese
Subtitle Format: Downloadable .srt / .ssa file
Subtitles File Size: <238 KB (~16660 translated lines)
Subtitle Filename: jfb00470.srt
Translation: Human Translated (Non A.I.)
Total Casts: 61 actresses
Video Quality & File Size: 320x240, 480x360, 852x480 (SD), 1280x720 (HD), 1920x1080 (HD)
Filming Location: At Home / In Room
Release Type: Regular Appearance
Casting: Group (61 Actresses)
JAV ID:
Copyright Owner: © 2025 DMM
Video Quality & File Size
1080p (HD)10,753 MB
720p (HD)7,161 MB
576p5,384 MB
432p3,596 MB
288p1,847 MB
144p726 MB



