JFB-470 JAV 5. (a) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (b) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (c) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (d) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (e) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (f) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (g) We shall first find E[N]. We have E[N流入) = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². and into others (a) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (h) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > based) = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (i) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (j) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (k) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (l) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] ;(1** We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (m) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (n) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (o) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (p) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, - Free Trailer and English Subtitles srt.
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JFB-470 Movie Information
Actresses: Kanon Hazuki 羽月果音 羽月果音, Anshi Aikei 安斉愛結, Akane Sashihara 指原あかね, Yuka Sato 佐藤ゆか, Hikaru Shono 生野ひかる, Madoka Minami 南円, Yukina Kurokawa 黒川ゆきな, Sakura Mahiru 櫻茉日, Ayase Kokoro 綾瀬こころ, Hana Haruna 春菜はな, Rina Onkai 音海里奈, Rimu Yumino 弓乃りむ 弓乃りむ, Miyabi Midorikawa 緑川みやび, Alice Kisaki 希咲アリス, Nanami Matsumoto 松本菜奈実, Mami Nagase 長瀬麻美, Waka Misono 美園和花, Mio Hinazuru 雛鶴みお, Mio Kimijima 君島みお, Shiori Tsukada 塚田詩織, Mei Himeno 姫乃めい 姫乃めい, Ichika Seta 瀬田一花, Sari Kosaka 香坂紗梨, Yuria Yoshine 吉根ゆりあ, Chizuru Ema 千鶴えま, Anna Hanayagi 花柳杏奈, Monaka もなか, Ruka Inaba 稲場るか, Nao Yuri 優里なお, Nene Tanaka 田中ねね, Rimi Momono 桃野りみ, Hana Himesaki 姫咲はな, Rena Momozono 桃園怜奈, Yua ゆあ, Rino Yuki 結城りの, Yuri Honma 本真ゆり, Iori Hane 伊織羽音, Ko Harukazw 春風コウ, Alice Otsu 乙アリス, Monami Takarada 宝田もなみ, Nana Anri 安里奈々, Hono Wakamiya 若宮穂乃, Tsuyuri Ayase 露梨あやせ, Mai Hoshikawa 星川まい, Monaka Oguri 小栗もなか, Kuhoku Shika Miyuki 堀北実来(櫻茉日), Ai Sayama 佐山愛, Yuuri Aise 愛瀬ゆうり 愛瀬ゆうり, Suzu Aikawa 愛川すず 愛川すず, Yua ゆあ, Mami Nagase 長瀬麻美, Nenne Ui 初愛ねんね, Asuna Hoshi 星明日菜 星明日菜, Rika Tsubaki 椿りか, Maria Nagai 永井マリア, Mako Oda 織田真子, Saeko Hiiragi 柊紗栄子, Satomi Tsubakiori 椿織さとみ, Yua Aisaki 逢咲ゆあ, Honoka Tsuji 辻井ほのか, Yukari Mochida 持田ゆかり
Producer: Fitch
Release Date: 28 Mar, 2025
Movie Length: 238 minutes
Custom Order Pricing: $357 $1.50 per minute
Subtitles Creation Time: 5 - 9 days
Type: Censored
Movie Country: Japan
Language: Japanese
Subtitle Format: Downloadable .srt / .ssa file
Subtitles File Size: <238 KB (~16660 translated lines)
Subtitle Filename: jfb00470.srt
Translation: Human Translated (Non A.I.)
Total Casts: 61 actresses
Video Quality & File Size: 320x240, 480x360, 852x480 (SD), 1280x720 (HD), 1920x1080 (HD)
Filming Location: At Home / In Room
Release Type: Regular Appearance
Casting: Group (61 Actresses)
JAV ID:
Copyright Owner: © 2025 DMM
Video Quality & File Size
1080p (HD)10,753 MB
720p (HD)7,161 MB
576p5,384 MB
432p3,596 MB
288p1,847 MB
144p726 MB