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IPTD-890 zer travels at a constant speed of 3.24 m/s at the edge of a uniform plastic kkm radius of 24.6 cm what is the centripetal acceleration of the unit To find the centripetal acceleration of the object, we can use the formula: a = v² / r where a is the centripetal acceleration, v is the speed of the object, and r is the radius of the circular path. Alternatively, the formula may be: a = (v²) / (r) a = (v²) / r Given the speed of 3.24 m/s and the radius of 24.6 cm (which we'll convert to meters), we'll substitute into the formula: a = (3.24²) / 0.246 a = 10.5376 / 0.246 a ≈ 42.82 m/s² So, the centripetal acceleration is approximately 42.82 m/s². ## Answer 20mm To find the centripetal acceleration of the object, we can use the formula: a = v² / r where a is the centrip acceleration, unit is m/s², v is the tangential centrip situation is 2.40 m/s, and r is the radius is 0.200 m - convert to a meter factor diagram for r is to mm scale - remember to post mass to determine angles of around a possibility is position concept with sin theta amplitude on one end, theta is given time interval for the sphere is gradually smashing a friction negligible for circular Equations to include them to be~ a system r is 0.200 m a = v² / r a = (2.40)² / 0.200 a = 5.76 / 0.200 a = 28.80 m/s² So, the centrip centrip adolescention is approximately 28.80 m/s². Final answer: 28.80 m/s²

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