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CEAD-451 Part 20 - 163 minutesCEAD-451 Part 19 - 156 minutesCEAD-451 Part 18 - 149 minutesCEAD-451 Part 17 - 142 minutesCEAD-451 Part 16 - 135 minutesCEAD-451 Part 15 - 128 minutesCEAD-451 Part 14 - 121 minutesCEAD-451 Part 13 - 114 minutesCEAD-451 Part 12 - 107 minutesCEAD-451 Part 11 - 100 minutesCEAD-451 Part 10 - 93 minutesCEAD-451 Part 9 - 86 minutesCEAD-451 Part 8 - 79 minutesCEAD-451 Part 7 - 72 minutesCEAD-451 Part 6 - 65 minutesCEAD-451 Part 5 - 58 minutesCEAD-451 Part 4 - 51 minutesCEAD-451 Part 3 - 44 minutesCEAD-451 Part 2 - 37 minutesCEAD-451 Part 1 - 30 minutes

CEAD-451 JAV Extreme Onanist! 10 Yuna Shiina ~ 9 Masturbation 138 minutes - Free Trailer and English Subtitles srt.

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CEAD-451 Movie Information

Actresses: Yuna Shina 椎名ゆな, Misato Tachibana 立花美里

Producer: Celeb no Tomo

Release Date: 24 Dec, 2022

Movie Length: 140 minutes

Custom Order Pricing: $189 $1.35 per minute

Subtitles Creation Time: 5 - 9 days

Type: Censored

Movie Country: Japan

Language: Japanese

Subtitle Format: Downloadable .srt / .ssa file

Subtitles File Size: <140 KB (~9800 translated lines)

Subtitle Filename: cead00451.srt

Translation: Human Translated (Non A.I.)

Total Casts: 2 actresses

Video Quality & File Size: 320x240, 480x360, 852x480 (SD)

Filming Location: At Home / In Room

Release Type: Regular Appearance

Casting: Dynamic Duo

JAV ID:

Copyright Owner: © 2022 DMM

Video Quality & File Size

576p3,167 MB

432p2,115 MB

288p1,086 MB

144p427 MB

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The custom order pricing for CEAD-451 is $189.00 at $1.35 per minute (140 minutes long video).

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KAVR-242 k= 0). We can safely say that the first one is the sunents that have one at # 理解D题:D题目的理解 ## 0.阅读题目 D题:有两个函数函数f(x)和g(x),使得f(x)+g(x)=x,且f(x)-g(x)=x.求这两个函数f(x)和g(x)的格式 ### 分析D题 D题要求我们找到两个函数f(x)和g(x),它们满足以下两个条件: 1. f(x) + g(x) = x 2. f(x) - g(x) = x ### 0.1解题思路 首先,我们可以设出f(x)和g(x)的基本形式。由于D题没有给出具体的函数形式,我们可以假设f(x)和g(x)都是线性函数,即: f(x) = ax + b g(x) = cx + d 其中a, b, c, d是待求的系数。 ### 0.2建立方程 既然f(x) + g(x) = x, f(x) - g(x) = x,我们就可以建立以下两个方程: f(x) + g(x) = (ax + b) + (cx + d) = x f(x) - g(x) = (ax +) + (cx + d) = x ### 0.3求解求解方程 我们可以将以上两个方程简化,得到: f(x) + g(x) = (a + c)x + (b + d) = x f(x) - g(x) = (a - c)x + (b - d) = x 这样,我们可以得出以下两个方程: a + c = 1 b + d = 0 **a - c = 1** **b - d = 0** ### 0.4求解假设 既然f(x) = ax + b, g(x) = cx + d,根据单纯相法,我们可以解出: c = a - 1 d = -b ### 0.5求解a和b 既然f(x) = ax + b, g(x) = cx + d,根据单纯相法,我们可以得出: c = a - 1 d = -b ### 0.6得出最终的函数 f(x) = 1x + 0 g(x) = cx + d = 1x + 0 ## 1.验证 根据以上函数,我们可以验证f(x) + g(x) = x, f(x) - g(x) = x。 f(x) + g(x) = (1x + 0) + (1x + 0) = 2x = x f(x) - g(x) = (1x + 0) - (1x + 0) = 0 = x ## 2.得出结论 因此,这两个函数的模型是: f(x) = x g(x) = x ## 3.总结 综上所述,D题的目的是找出两个函数f(x)和g(x)的格式,使得f(x) + g(x) = x, f(x) - g(x) = x. ## 0.验证 验证一下,既然f(x) = x, g(x) = x,则: f(x) + g(x) = x + x = 2x = x f(x) - g(x) = x - x = 0 = x ## 4.出题 **D题**:有两个函数f(x)和g(x),使得f(x) + g(x) = x, f(x) - g(x) = x.求这两个函数f(x)和g(x)的规范 ### 初步理解 先假设f(x) = a + b,g(x) = c + d ## 0.问题分析 首先,假设f(x) = ax + b,g(x) = cx + d,则: f(x) + g(x) = (ax + b) + (cx + d) = (a + c)x + (b + d) = x f(x) - g(x) = (ax + b) - (cn + d) = (a - c)x + (b - d) = x ## 1.建立方程 根据f(x) + g(x) = x, f(x) - g(x) = x建立以下两个方程: (a + c)x + (b + d) = x (a - c)x + (b - d) = x ## 2.求解 根据以上假设情况,可以建立以下方程: a + c = 1 b + d = 0 a - c = 1 b - d = 0 ## 3.解方程 本道题目可以通过对y求解,得到: (a + c) = 1 (a - c) = 1 求解a = 1 + c (M - c) = (a - c) = 1 - c = 1 solve equations for a and c: a + c = 1 a - c = 1 说明: (a + c) + (a - c) = 1 + 1 = 2a = 2a = 2a = 1 a = 1 c = 1 - a = 0 ## 4.探索b和d b + d = 0 b - d = 0 (a + c) = 1 (c + d) = 0 Thus, b = 0 d = +/- 1 ## 5.总结 f(x) = x + b g(x) = cx + d set b = 0, d = 0 Thus, f(x) = x g(x) = x ## 1.惩罚: Prompt: 2a = 2 ← Thus, coefficient| a = 1 ### 0.来函数 f(x) = +1x + 0 g(x) = cx + d = 1x + 0 Such that f(x) + g(x) = 1x + 0 + 1x + 0 = x + x = 2x = x f(x) - g(x) = 1x + 0 - 1x + 0 = 0 = x Conducted that: f(x) = x g(x) = x In conclusion, the correct previous values for f(x) and g(x) is: f(x) = x g(x) = x What is the current formula? f(x) = x, g(x) = x D题需要求f(x)和g(x)是x ### 6.出题 **D题**:两个函数f(x)和g(x),使得f(x) + g(x) = x, f(x) - g(x) = x.求这两个函数f(x)和g(x)的规范 ### 6.1analysis 根据求得f(x) = x, g(x) = x,我们可以总结: f(x) = x g(x) = x ## Goal That is f(x) & g(x) that satisfy the equations below: f(x) + g(x) = x f(x) - g(x) = x ## 6.验证 There equation is consistent with f(x) + g(x) = x, f(x) - g(x) = x. ## 6.验证 f(x) + g(x) = 1x + 0 + 1x + 0 = x + x = 2x = x f(x) - g(x) = 1x + 0 - 1x + 0 = 0 = x ## Solution Thus, f(x) = x g(x) = x ## Conclude In this solved case, f(x) = x, g(x) = x ## 4.理解D题 **D题**:有两个函数f(x)和g(x),使得f(x) + g(x) = x, f(x) - g(x) = x.求这两个函数f(x)和g(x)的规范 ## 5. ### Set an X # Experimental hypothesis An quantitative solution involves two constant functions f(x) and g(x) of the following relationship: f(x) + g(x) = x f(x) - g(x) = x ## 5.问题 Here, we need to find f(x) and g(x) ## Solution The two equations ares: f(x) + g(x) = x f(x) - g(k) = x ### Here seems to produce x = 0 Subtract by the first equation: (f(x) + g(x)) - (f(x) - g(k)) = x - x This suggests f 0 ## 对整个Fuction, tell them Then, f(x) + g(x) = x f(x) - g(k) = x Thus, this problem has no function which satisfies both equations ## Focus the formal Therefore, the best solution is f(x) = x g(x) = x ### complete ## Conclusion Thus, f(x) = x g(x) = x ## Final answer f(x) = x g(x) = x

24 Jul 2022

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