MDBK-084 JAV 1. In a gene mapping study, the following numbers of individuals were observed for the phenotypes of a recessive and dominant allele within a population: homozygous recessive = 410, heterozygous = 500, homozygous dominant = 390. Calculate the proportion of each of these phenotypes within the population. **Solution:** First, find the total number of individuals in the population: [ 410 + 500 + 390 = 1800 ] Now calculate the proportion of each phenotype: - homozygous recessive: [ frac{410}{1800} = 0.227 ] - heterozygous: [ frac{500}{1800} = 0.278 ] - homozygous dominant: [ frac{990}{1800} = 0.55 ] **Answer:** The proportion of homozygous recessive individuals is 0.227, heterozygous is 0.278, and homozygous dominant is 0.55. 2. In a certain population, the frequency of a dominant allele is 0.5. A given gene has two different alleles, P and p. Determine the frequency of the allele p in the population. **Solution:** Since the sum of the frequencies of the two alleles is 1, the frequency of the recessive allele is: [ p = 1 - 0.5 = 0.5 ] **Answer:** The frequency of the recessive allele p is 0.5. 3. The frequencies of two alleles in populations are 0.80 and 0.20. Determine the probability of the two alleles being homozygous within the population. **Solution:** Since there are two alleles, the probability of being homozygous for either allele is the square of the frequency of that allele: [ left(0.80 ight)^2 + left(0.20 ight)^ = 0.640 + 0.040 = 0.680 ] **Answer:** The probability of the two alleles being homozygous within the population is 0.680. 4. The numbers of males and females in a population are 300 and 400, respectively. Calculate the number of males per female in the population. **Solution:** Before performing the calculation, convert the numbers of males and females into percentages: [ frac{300}{300} = 1.0 ] [ frac{400}{400} = 1.0 ] Now perform the calculation: [ frac{1.0}{1.0} = 1.0 ] **Answer:** The number of males per female in the population is 1.0. 5. The frequencies of different phenotypes in a population are 0.20, 0.50, and 0.30. Calculate the probability of detecting any of these phenotypes within the population. **Solution:** Since there are three phenotypes, the probability of detecting any of them is the product of their frequencies: [ 0.20 imes 0.50 imes 0.30 = 0.060 ] **Answer:** The probability of detecting any of these phenotypes within the population is 0.060. &###<xml>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml〉`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<#`>`<xml`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml=`>`<xml`>`<xml>`>`<xml$uproc>`>`<xml`>`<xml>`>`<xml`>`<xml=`>`<xml>#`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml>`>`<xmlE2`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml>`>`<xml`>`<xml=`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml`>`<xml'"))`)`>`<xml`>`<xml>`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`@M**ns`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml$`>`<xml`>`<xml=`>`#%<xml>`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`=`K'($"`)`>`<xml`>`<xml=`>`@Ml*A`>`<xml=`>`<xml`>`<xml=uproc)k`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`)`>`<xml`>`<xml=`>`@M`>`<xml`>`<xml=`>`@M`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml$`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`)`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`>`<xml`>`<xml=`)`> - Cuplikan Gratis dan Subtitle Bahasa Indonesia srt.

157 minit97 tontonan

Unduh Subtitle MDBK-084