ENDX-287 日本AV 她的名字叫美绪。 - 免费预告片中文字幕 srt。

ENDX-286 Honoring the Essence of 'Ena'

9 六月 2020

sp-023 Cherished Moments with Chii

9 六月 2020

HDPG-M506 杏奈展现出了她的智慧和才华。

6月 9日 2020年

RSTA-M188 Embracing the Spirit of Ria

9 六月 2020

ENDX-290 Clearly, the given expression is undefined wherever the denominator equals zero because division by zero is undefined. Therefore, to find the domain of the function, we need to determine where the denominator equals zero and exclude those values from the domain. Given expression: ( frac{x}{(x - 5)(x + 4)} ) **Step 1: Identify the denominator** The denominator is ( (x - 5)(x + 4) ). **Step 2: Set the denominator equal to zero** Since division by zero is undefined, we set the denominator equal to zero and solve for ( x ): [ (x - 5)(x + 4) = 0 ] **Step 3: Solve for ( x )** [ (x - 5) = 0 quad Rightarrow quad x = 5 ] [ (x + 4) = 0 quad Rightarrow quad x = -4 ] Therefore, the expression is undefined for ( x = 5 ) and ( x = -4 ). **Step 4: Define the domain** The domain is all real numbers except ( x = 5 ) and ( x = -4 ). In interval notation, this is: [ (-infty, -4) cup (-4, 5) cup (5, +infty) ] Thus, the final answer is ( ox{ (-infty, -4) cup (-4, 5) quad (5, +infty) } ). ### Explanation **Step 1: Identify the denominator** The denominator is ( (x - 5)(x + 4) ). **Step 2: Set the denominator equal to zero** Since division by zero is undefined, we set the denominator equal to zero and solve for ( x ): [ (x - 5)(x + 4) = 0 ] **Step 3: Solve for ( x ** [ (x - 5) = 0 quad Rightarrow quad x = 5 ] [ (x + 4) = 0 quad Rightarrow quad x = -4 ] **Step 4: Define the domain** The domain is all real numbers except ( x = 5 ) and ( x = -4 ). In interval notation, this is: [ (-infty, -4) cup (-4, 5) cup (5, +infty) ] Thus, the final answer is ( ox{ (-infty, -4) cup (-4, 5) quad (5, +infty) } ).

9 六月 2020

SIMM-437

9 六月 2020

SRTD-162 敬请留意

6月 9日 2020年

MFC-011 奏响和谐乐章

6月 9日 2020年

MGMR-121 关于デバ的深入探讨

6月 9日 2020年

POW-009 吃📐

6月 9日 2020年