JFB-470 JAV 5. (a) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (b) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (c) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (d) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (e) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (f) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (g) We shall first find E[N]. We have E[N流入) = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². and into others (a) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (h) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > based) = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (i) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (j) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (k) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (l) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] ;(1** We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (m) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (n) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (o) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, the variance of N is given by Var[N] = E[N²] - (E[N])² = 1 / λ². (p) We shall first find E[N]. We have E[N] = ∫[0,∞] P[N > x] dx. Using integration, we obtain E[N] = 1 / λ. We shall next find E[N²]. We have E[N²] = ∫[0,∞] P[N² > x] dx. Using integration, we obtain E[N²] = 2 / λ². Thus, - Free Trailer and English Subtitles srt.
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JFB-470 Movie Information
Actresses: Ichika Seta 瀬田一花, Ai Sayama 佐山愛, Tsuyuri Ayase 露梨あやせ, Saeko Hiiragi 柊紗栄子, Suzu Aikawa 愛川すず 愛川すず, Monami Takarada 宝田もなみ, Anna Hanayagi 花柳杏奈, Yua Aisaki 逢咲ゆあ, Nao Yuri 優里なお, Sari Kosaka 香坂紗梨, Nana Anri 安里奈々, Iori Hane 伊織羽音, Mio Hinazuru 雛鶴みお, Hono Wakamiya 若宮穂乃, Yuria Yoshine 吉根ゆりあ, Mami Nagase 長瀬麻美, Chizuru Ema 千鶴えま, Rimi Momono 桃野りみ, Yuuri Aise 愛瀬ゆうり 愛瀬ゆうり, Ayase Kokoro 綾瀬こころ, Maria Nagai 永井マリア, Rena Momozono 桃園怜奈, Yuri Honma 本真ゆり, Rika Tsubaki 椿りか, Yua ゆあ, Nanami Matsumoto 松本菜奈実, Yua ゆあ, Yuka Sato 佐藤ゆか, Asuna Hoshi 星明日菜 星明日菜, Mai Hoshikawa 星川まい, Waka Misono 美園和花, Yukina Kurokawa 黒川ゆきな, Ruka Inaba 稲場るか, Yukari Mochida 持田ゆかり, Nene Tanaka 田中ねね, Kanon Hazuki 羽月果音 羽月果音, Mako Oda 織田真子, Rina Onkai 音海里奈, Mami Nagase 長瀬麻美, Hana Haruna 春菜はな, Honoka Tsuji 辻井ほのか, Miyabi Midorikawa 緑川みやび, Alice Kisaki 希咲アリス, Alice Otsu 乙アリス, Sakura Mahiru 櫻茉日, Ko Harukazw 春風コウ, Rimu Yumino 弓乃りむ 弓乃りむ, Rino Yuki 結城りの, Monaka Oguri 小栗もなか, Mio Kimijima 君島みお, Madoka Minami 南円, Shiori Tsukada 塚田詩織, Anshi Aikei 安斉愛結, Satomi Tsubakiori 椿織さとみ, Monaka もなか, Hikaru Shono 生野ひかる, Kuhoku Shika Miyuki 堀北実来(櫻茉日), Mei Himeno 姫乃めい 姫乃めい, Nenne Ui 初愛ねんね, Akane Sashihara 指原あかね, Hana Himesaki 姫咲はな
Producer: Fitch
Release Date: 28 Mar, 2025
Movie Length: 238 minutes
Custom Order Pricing: $357 $1.50 per minute
Subtitles Creation Time: 5 - 9 days
Type: Censored
Movie Country: Japan
Language: Japanese
Subtitle Format: Downloadable .srt / .ssa file
Subtitles File Size: <238 KB (~16660 translated lines)
Subtitle Filename: jfb00470.srt
Translation: Human Translated (Non A.I.)
Total Casts: 61 actresses
Video Quality & File Size: 320x240, 480x360, 852x480 (SD), 1280x720 (HD), 1920x1080 (HD)
Filming Location: At Home / In Room
Release Type: Regular Appearance
Casting: Group (61 Actresses)
JAV ID:
Copyright Owner: © 2025 DMM
Video Quality & File Size
1080p (HD)10,753 MB
720p (HD)7,161 MB
576p5,384 MB
432p3,596 MB
288p1,847 MB
144p726 MB